Writing Math Formulas Using MathJax

$$f\left(a\right)=\frac{1}{2\pi i}{\oint }_{\gamma }\frac{f\left(z\right)}{z-a}dz$$

Configuration

To enable MathJax support, just set plugins.mathjax = true in your theme _config.yml file.

# Plugins
plugins:
    ...
    mathjax: true # options: true, false

TeX and LaTeX input

Please be noted that when you write Tex/LaTeX in Markdown files, you need to use escape characters to prevent certain signs from being processed by Markdown interpreter.

Input

When $a \ne 0$, there are two solutions to \\(ax^2 + bx + c = 0\\) and they are
$$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$

Result

When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$

MathML input

Attention: please be noted that newline characters will be transformed to <br> tag by Markdown interpreter and this will interfere with MathML notation. Please write all MathML inline.

Input

When<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>a</mi><mo>&#x2260;</mo><mn>0</mn></math>, there are two solutions to <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>a</mi><msup><mi>x</mi><mn>2</mn></msup><mo>+</mo> <mi>b</mi><mi>x</mi><mo>+</mo> <mi>c</mi> <mo>=</mo> <mn>0</mn></math> and they are
<math xmlns="http://www.w3.org/1998/Math/MathML" display="block"><mi>x</mi> <mo>=</mo><mrow><mfrac><mrow><mo>&#x2212;</mo><mi>b</mi><mo>&#x00B1;</mo><msqrt><msup><mi>b</mi><mn>2</mn></msup><mo>&#x2212;</mo><mn>4</mn><mi>a</mi><mi>c</mi></msqrt></mrow><mrow> <mn>2</mn><mi>a</mi> </mrow></mfrac></mrow><mtext>.</mtext></math>

Result

When $a\ne 0$, there are two solutions to $a{x}^2+bx+c=0$ and they are $$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\text{.}$$

AsciiMath input

Attention: please be noted that when you write AsciiMath in Markdown files, you need to use escape characters to prevent certain signs from being processed by Markdown interpreter.

Input

When \`a != 0\`, there are two solutions to \`ax^2 + bx + c = 0\` and they are<p style="text-align:center">\`x = (-b +- sqrt(b^2-4ac))/(2a) .\`</p>

Result

When `a != 0`, there are two solutions to `ax^2 + bx + c = 0` and they are

`x = (-b +- sqrt(b^2-4ac))/(2a) .`